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'sdeath y3
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WebCalculus. Find dy/dx x^3+y^3=3xy^2. x3 + y3 = 3xy2 x 3 + y 3 = 3 x y 2. Differentiate both sides of the equation. d dx (x3 +y3) = d dx (3xy2) d d x ( x 3 + y 3) = d d x ( 3 x y 2) Differentiate the left side of the equation. Tap for more steps... 3x2 + 3y2y' 3 x 2 + 3 y 2 y ′. Differentiate the right side of the equation.
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